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C# – Floyd–Warshall Algorithm – Csharp Star

learningcode_x1mckf by learningcode_x1mckf
September 4, 2022
in C#
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C# – Knapsack Problem – Csharp Star
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On this article, we’ll be taught C# implementation of Floyd–Warshall Algorithm for figuring out the shortest paths in a weighted graph with optimistic or destructive edge weights

 

utilizing System;
utilizing System.Collections.Generic;
utilizing System.Linq;
utilizing System.Textual content;
utilizing System.Diagnostics;

namespace FloydWarshallAlgorithm
{
    class FloydWarshallAlgo
    {

        public const int cst = 9999;

        non-public static void Print(int[,] distance, int verticesCount)
        
            Console.WriteLine("Shortest distances between each pair of vertices:");

            for (int i = 0; i < verticesCount; ++i)
            
                for (int j = 0; j < verticesCount; ++j)
                
                    if (distance[i, j] == cst)
                        Console.Write("cst".PadLeft(7));
                    else
                        Console.Write(distance[i, j].ToString().PadLeft(7));
                

                Console.WriteLine();
            
        

        public static void FloydWarshall(int[,] graph, int verticesCount)
        
            int[,] distance = new int[verticesCount, verticesCount];

            for (int i = 0; i < verticesCount; ++i)
                for (int j = 0; j < verticesCount; ++j)
                    distance[i, j] = graph[i, j];

            for (int ok = 0; ok < verticesCount; ++ok)
            
                for (int i = 0; i < verticesCount; ++i)
                
                    for (int j = 0; j < verticesCount; ++j)
                    
                        if (distance[i, k] + distance[k, j] < distance[i, j])
                            distance[i, j] = distance[i, k] + distance[k, j];
                    
                
            

            Print(distance, verticesCount);
        
        static void Most important(string[] args)
        
            int[,] graph = 
                           0,   6,  cst, 11 ,
                           cst, 0,   4, cst ,
                           cst, cst, 0,   2 ,
                           cst, cst, cst, 0 
                           ;

            FloydWarshall(graph, 4);
        
    }
}

 

Output:

Shortest distances between each pair of vertices:
0 6 10 11
cst 0 4 6
cst cst 0 2
cst cst cst 0

 
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